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Category:Automobile manufacturers of France Category:Vehicle technology companies Category:Technology companies of FranceQ: Why can't we use long on local variables? While looking at Java Generics I came across this: public class Foo { private long bar; public void doStuff() { bar = 3; } } Long cannot be assigned to. And yet, a method call is fine: Foo foo = new Foo(); foo.doStuff(); Is this because it's actually an enum in disguise? A: Here's where things get interesting, because you're invoking the generic type of the constructor to construct a Foo instance, which is why your code compiles. However, when you call doStuff, you're invoking an instance method of the Foo type, which means T is substituted for the actual type, Long. So this line does the same thing as And long cannot be assigned to, because Number can't be assigned to. Because T is expected to be a supertype of Number, it is not allowed. You can think of it as a type erasure -- the compiler knows that at runtime there will be no clashes, but it is a compile-time mistake for the compiler to be aware of the same thing. From the JLS §4.10.2: If S is a wildcard (§4.5.1), then the following are also the results of this expression: new S(); That's pretty much what happens when you instantiate an anonymous class with a generic type parameter. I assume you're confused because the warning you see comes from the Java compiler, not the Java runtime. Q: How to insert/update a new entry into Mongodb using node.js? I have the following schema of a collection of blog posts: { "_id" : ObjectId("5823a958ab84bdbd3b06e1eb"), "




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